Topcoder SRM 515(Div.2) report

I used both of JAVA and C++ in this contest.

Start and solve 250-score problem with JAVA. My source code is drag! I'm not good at JAVA and C++, so I write code very slow! Solve with score 176.96.

Next, I solve 500-score problem with C++. I enjoy this problem, however, system test not passed. Out of contest, I resolve this, I get system test passed. The source in this article is correct.

I explain my algorithm of 500-score(=div.1 250-score) problem.
We can get minute from hourHand. HourHand%30*2 means the time's minute. Then, we can get minute-hand degree from the mark means 12(=0). The differ of hourHand and minuteHand is added to mm*6. We can get hour!

Problems are here.
Score:176.96,Rank:694/1093,Rate:866->823.
I'm bad score recently. I need writing many C++/JAVA source code!


[Level-one (JAVA)]

public class FortunateNumbers{
    public static int getFortunate(int[] a, int[] b, int[] c){
int sum=0;
int[][][] logs=new int[a.length][b.length][c.length];
for(int i=0;i<a.length;i++){
   for(int j=0;j<b.length;j++){
for(int k=0;k<c.length;k++){
   int tmp=a[i]+b[j]+c[k];
   if(isFortunate(tmp)==1) logs[i][j][k]=tmp;
   else logs[i][j][k]=0;
}
   }
}
for(int i=0;i<a.length;i++){
   for(int j=0;j<b.length;j++){
for(int k=0;k<c.length;k++){
   if(logs[i][j][k]==0) continue;
   for(int p=0;p<a.length;p++){
for(int q=0;q<b.length;q++){
   for(int r=0;r<c.length;r++){
if(i==p&&j==q&&k==r) continue;
if(logs[i][j][k]==logs[p][q][r]) logs[p][q][r]=0;
   }
}
   }
   sum++;
}
   }
}
return sum;
    }

    public static int isFortunate(int n){
while(n>0){
   if(n%10!=5 && n%10!=8) return 0;
   n/=10;
}
return 1;
    }
}


[Level-two (C++)]

#include<cstdio>
#include<cstring>
#include<iostream>
#include<string>

using namespace std;

class RotatedClock{
public:
  string getEarliest(int hourHand, int minuteHand){
    int hh=-1,mm=hourHand%30*2;
    int mdeg=mm*6;
    int dif=hourHand-minuteHand;
    if(dif<0) dif+=360;
    int hdeg=(mdeg+dif)%360;
    if(hdeg%30*2==mm) hh=hdeg/30;
    char str[10];
    if(hh>=0 && mm>=0){
      sprintf(str,"%02d:%02d",hh,mm);
      return string(str);
    }else return "";
  }
};